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How many three digit natural numbers are divisible by 5?

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#### Solution

The first three digit natural number divisible by 5 is 100.

Common difference d = 5

Last three digit natural number divisible by 5 is 995

We know that,

t_{n} = a + (n -1) d

995 = 100 + (n -1) 5

895 = 5 (n -1)

179 = n -1

n =180

Hence, there are 180 three digit natural numbers divisible by 5.

Concept: Introduction to Sequence

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