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How Many Four-digit Numbers Can Be Formed with the Digits 3, 5, 7, 8, 9 Which Are Greater than 7000, If Repetition of Digits is Not Allowed? - Mathematics

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How many four-digit numbers can be formed with the digits 3, 5, 7, 8, 9 which are greater than 7000, if repetition of digits is not allowed?

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Solution

Since the  number has to be greater than 7000, the thousand's place can only be filled by three digits, i.e. 7, 8 and 9.
Now, the hundred's place can be filled with the remaining 4 digits as the repetition of the digits is not allowed.
The ten's place can be filled with the remaining 3 digits.
The unit's place can be filled with the remaining 2 digits.
Total numbers that can be formed = 3\[\times\]4\[\times\]3\[\times\]2 = 72

Concept: Combination
  Is there an error in this question or solution?

APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 16 Permutations
Exercise 16.2 | Q 20 | Page 15

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