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Sum
How many different words are formed if the letter R is used thrice and letters S and T are used twice each?
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Solution
When R is used thrice, S is used twice and T is used twice,
∴ Total number of letters available = 7, of which S and T repeat 2 times each, R repeats 3 times.
∴ Required number of arrangements = `(7!)/(2!2!3!)`
= `(7 xx 6 xx 5 xx 4 xx 3!)/(2xx1xx2xx1xx3!)`
= 7 × 6 × 5
= 210
∴ 210 different words can be formed with the letter R is used thrice and letters S and T are used twice each.
Concept: Permutations When All Objects Are Not Distinct
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