Question

 How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?

Answer 1

For x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is given by Ohm’s law asV= IR
R= V/I
Where,
Supply voltage, V= 220 V
Current, I = 5 A
Equivalent resistance of the combination = R,given as

`1/R=x xx(1/176)`

`R=176/x`

From Ohm's law

`V/I=176/x`

`x=(176xxI)/V=(176xx5)/220=4`

Therefore, four resistors of 176 Ω are required to draw the given amount of current.