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How Does the Electric Flux Due to a Point Charge Enclosed by a Spherical Gaussian Surface Get Affected When Its Radius is Increased? - Physics

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How does the electric flux due to a point charge enclosed by a spherical Gaussian surface get affected when its radius is increased?

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Solution

According to Gauss's law, flux through a closed surface is given by

`phi = q/ε_0`

Here, q is the charge enclosed by the Gaussian surface.

Since, on increasing the radius of the Gaussian surface, charge q remains unchanged, the flux through the spherical Gaussian surface will not be affected when its radius is increased.

Concept: Electric Flux
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