#### Question

Calculate the de-Broglie wavelength of the electron orbitting in the n = 2 state of hydrogen atom.

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#### Solution

As we know,

`mvr_2=(nh)/(2pi)`

The de-Broglie wavelength is given as,

`lambda=h/(mv)=h/(nh)xx(2pir_2)=pir_2`

As r_{2}=0.529×n^{2}×10^{−10} m

Therefore, λ=π×0.529×10^{−10}×n^{2}=3.14×0.529×10^{−10}×2^{2}≃6.64×10^{−10} m

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#### Reference Material

Solution for question: Calculate the De-broglie Wavelength of the Electron Orbitting in the N = 2 State of Hydrogen Atom. concept: null - Heisenberg and De Broglie Hypothesis. For the courses CBSE (Commerce), CBSE (Arts), CBSE (Science)