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From the Top of a Lighthouse, 100 M High the Angles of Depression of Two Ships on Opposite Sides of It Are 48° and 36° Respectively. Find the Distance Between the Two Ships to the Nearest Metre. - ICSE Class 10 - Mathematics

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ConceptHeights and Distances - Solving 2-D Problems Involving Angles of Elevation and Depression Using Trigonometric Tables

Question

From the top of a lighthouse, 100 m high the angles of depression of two ships on opposite sides of it are 48° and 36° respectively. Find the distance between the two ships to the nearest metre.

Solution

From right angle Δ ADC,

`(AD)/(CD) = tan 36^@`

`=>100/y = tan 36^@`

`=> 100/tan 36^@ = 100/0.7265  => y = 137.638 m`

From right angle Δ ADB

`100/x = tan 48^@ => x = 100/1.1106 = 90.04 m`

∴ Distance between the ships = x + y

= 137.638 + 90.04 = 227.678 m

= 228 m (approx)

  Is there an error in this question or solution?

APPEARS IN

 2009-2010 (March) (with solutions)
Question 8.3 | 4.00 marks
Solution From the Top of a Lighthouse, 100 M High the Angles of Depression of Two Ships on Opposite Sides of It Are 48° and 36° Respectively. Find the Distance Between the Two Ships to the Nearest Metre. Concept: Heights and Distances - Solving 2-D Problems Involving Angles of Elevation and Depression Using Trigonometric Tables.
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