Solution - Heights and Distances



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The elevation of a tower at a station A due north of it is α and at a station B due west of A is β. Prove that the height of the tower is `\frac{AB\sin \alpha \sin \beta }{\sqrt{\sin^{2}\alpha -\sin ^{2}\beta `


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Reference Material

Solution for concept: Heights and Distances. For the course 8th-10th CBSE