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Solution - Heights and Distances

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Question

The elevation of a tower at a station A due north of it is α and at a station B due west of A is β. Prove that the height of the tower is `\frac{AB\sin \alpha \sin \beta }{\sqrt{\sin^{2}\alpha -\sin ^{2}\beta `

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Reference Material

Solution for concept: Heights and Distances. For the course 8th-10th CBSE
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