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Height and base of a right angled triangle are 24 cm and 18 cm. Find the length of its hypotenus?

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#### Solution

In ∆PQR, ∠Q = 90°

∴ PR^{2} = PQ^{2} + QR^{2} ......[Pythagoras theorem]

= 24^{2} + 18^{2}

= 576 + 324

= 900

∴ PR = `sqrt(900)`

= 30 cm

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