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Consider the Situation Shown in Figure (28-e5). the Frame is Made of the Same Material and Has a Uniform Cross-sectional Area Everywhere. Calculate the Amount of Heat Flowing per Second - Physics

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Question

Consider the situation shown in the figure . The frame is made of the same material and has a uniform cross-sectional area everywhere. Calculate the amount of heat flowing per second through a cross section of the bent part if the total heat taken out per second from the end at 100°C is 130 J.

Solution

`R_{BC} = 1/{KA }= 1/{KA}`

`R_{CD} = 1/{KA }= 60/{KA}`

`R_{CD} = 5/{KA} ,  R_{AB} = 20/M , R_{EF} =  20/{KA}`

Let ;

`R_1 = R_{BC} + R_{CD} + R_{DE} = 70/{KA}`

Let :

`R_{BE} = 60/{KA} = R_2

q = q1 + q2        ...............(1)

R1 and R2 are in parallel, so total heat across R1 and R2 will be same.

⇒ `q_1R_2 = q_2R_2`

`q_1xx 70/{KA} = q_2xx 60/{KA}`

`7q_1 = 6q_2`

`{7q_1}/{6}= q_2`

From equation (1) and (2),

q = q_1 + {7q_1}/6`

`q = {13q_1}/6`

`q=130  J`
`130 = 13Qq_1`
q1 = 60 J/sec

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Solution Consider the Situation Shown in Figure (28-e5). the Frame is Made of the Same Material and Has a Uniform Cross-sectional Area Everywhere. Calculate the Amount of Heat Flowing per Second Concept: Heat Transfer - Conduction.
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