HCl is added to a hydrocarbon ‘A’ (C4H8) to give a compound ‘B’ which on hydrolysis with aqueous alkali forms tertiary alcohol ‘C’ (C4H10O). Identify ‘A’ ,‘B’ and ‘C’. - Chemistry

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Short Note

HCl is added to a hydrocarbon ‘A’ (C4H8) to give a compound ‘B’ which on hydrolysis with aqueous alkali forms tertiary alcohol ‘C’ (C4H10O). Identify ‘A’ ,‘B’ and ‘C’.

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Solution

\[\begin{array}{cc}
\ce{CH3\phantom{..............................}}\ce{CH3\phantom{.............................}}\ce{CH3\phantom{}}\\
|\phantom{..................................}|\phantom{.................................}|\\
\ce{\underset{\text{2-Methylprop-1-ene}}{H3C - C = CH2} +{ HCl} ->[Markovnikov][rule] H3C - C - CH3->[KOH(aq.) Hydrolysis][\triangle] H3C - C - CH3}\\
\ce{(C4H8)}\phantom{...............................}|\phantom{.................................}|\phantom{...}\\
\phantom{..............}\ce{(A)}\phantom{.......................}\ce{\underset{\text{2-Chloro-2-methylpropane (B)}}{Cl}}\phantom{.........}\ce{\underset{\text{2-Hydroxy-2-methylpropane (C4H10O)(C)}}{OH}}\\
\end{array}\]

Concept: Chemical Properties
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Chapter 10: Halogen Derivatives - Exercises [Page 233]

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Balbharati Chemistry 12th Standard HSC for Maharashtra State Board
Chapter 10 Halogen Derivatives
Exercises | Q 7.1 | Page 233

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