Greenlight is an incident at the polarising angle on a certain transparent medium. The angle of refraction is 30°. Find (i) polarising angle, and (ii) refractive index of the medium. - Physics

Advertisement Remove all ads
Answer in Brief

Greenlight is an incident at the polarising angle on a certain transparent medium. The angle of refraction is 30°.
Find
(i) polarising angle, and
(ii) refractive index of the medium.

Advertisement Remove all ads

Solution

(i) when the light is incident at the polarizing angle, the angle of refraction and angle of polarization are related according to the equation,

∠ip + ∠r = 90°

The angle of refraction is given as, 30°. So the angle of polarization, ∠ip = 90° - 30° = 60°

(ii) Applying Snell's law, we can write, the refractive index of the transparent media,` mu = sin"i"_"p"/sin "r"`

⇒ `mu = sin60^@/sin30^@ = (sqrt3/2)/(1/2) = sqrt3`

⇒ ` = mu sqrt3`

Concept: Polarisation
  Is there an error in this question or solution?

APPEARS IN

Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×