PUC Karnataka Science Class 12Department of Pre-University Education, Karnataka
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# The Least and Greatest Values of F(X) = X3 − 6x2+9x in [0,6], Are (A) 3,4 (B) 0,6 (C) 0,3 (D) 3,6 - PUC Karnataka Science Class 12 - Mathematics

#### Question

The least and greatest values of f(x) = x3$-$ 6x2+9x in [0,6], are ___________ .

• 3, 4

• 0, 6

• 0, 3

• 3, 6

• 0, 54

#### Solution

$\text { Given: } f\left( x \right) = x^3 - 6 x^2 + 9x$

$\Rightarrow f'\left( x \right) = 3 x^2 - 12x + 9$

$\text { For a local maxima or a local minima, we must have }$

$f'\left( x \right) = 0$

$\Rightarrow 3 x^2 - 12x + 9 = 0$

$\Rightarrow x^2 - 4x + 3 = 0$

$\Rightarrow \left( x - 1 \right)\left( x - 3 \right) = 0$

$\Rightarrow x = 1, 3$

$\text { Now,}$

$f\left( 0 \right) = 0^3 - 6 \left( 0 \right)^2 + 9\left( 0 \right) = 0$

$f\left( 1 \right) = 1^3 - 6 \left( 1 \right)^2 + 9\left( 1 \right) = 1 - 6 + 9 = 4$

$f\left( 3 \right) = 3^3 - 6 \left( 3 \right)^2 + 9\left( 3 \right) = 27 - 54 + 27 = 0$

$f\left( 6 \right) = 6^3 - 6 \left( 6 \right)^2 + 9\left( 6 \right) = 216 - 216 + 54 = 54$

The least and greatest values of f(x) = x3- 6x2+9x in [0, 6] are 0 and 54, respectively.

#### Notes

The question in the book has some error. So, none of the options are matching with the solution. The solution here is according to the question given in the book.

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Solution The Least and Greatest Values of F(X) = X3 − 6x2+9x in [0,6], Are (A) 3,4 (B) 0,6 (C) 0,3 (D) 3,6 Concept: Graph of Maxima and Minima.
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