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# Solution for The Least and Greatest Values of F(X) = X3 − 6x2+9x in [0,6], Are (A) 3,4 (B) 0,6 (C) 0,3 (D) 3,6 - CBSE (Science) Class 12 - Mathematics

#### Question

The least and greatest values of f(x) = x3$-$ 6x2+9x in [0,6], are

(a) 3,4
(b) 0,6
(c) 0,3
(d) 3,6

#### Solution

$\text { Given: } f\left( x \right) = x^3 - 6 x^2 + 9x$

$\Rightarrow f'\left( x \right) = 3 x^2 - 12x + 9$

$\text { For a local maxima or a local minima, we must have }$

$f'\left( x \right) = 0$

$\Rightarrow 3 x^2 - 12x + 9 = 0$

$\Rightarrow x^2 - 4x + 3 = 0$

$\Rightarrow \left( x - 1 \right)\left( x - 3 \right) = 0$

$\Rightarrow x = 1, 3$

$\text { Now,}$

$f\left( 0 \right) = 0^3 - 6 \left( 0 \right)^2 + 9\left( 0 \right) = 0$

$f\left( 1 \right) = 1^3 - 6 \left( 1 \right)^2 + 9\left( 1 \right) = 1 - 6 + 9 = 4$

$f\left( 3 \right) = 3^3 - 6 \left( 3 \right)^2 + 9\left( 3 \right) = 27 - 54 + 27 = 0$

$f\left( 6 \right) = 6^3 - 6 \left( 6 \right)^2 + 9\left( 6 \right) = 216 - 216 + 54 = 54$

The least and greatest values of f(x) = x3- 6x2+9x in [0, 6] are 0 and 54, respectively.
Disclaimer: The question in the book has some error. So, none of the options are matching with the solution. The solution here is according to the question given in the book.

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Solution for question: The Least and Greatest Values of F(X) = X3 − 6x2+9x in [0,6], Are (A) 3,4 (B) 0,6 (C) 0,3 (D) 3,6 concept: Graph of Maxima and Minima. For the courses CBSE (Science), CBSE (Commerce), PUC Karnataka Science, CBSE (Arts)
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