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# Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell? - CBSE (Science) Class 12 - Chemistry

ConceptCrystal Lattices and Unit Cells - Primitive and Centred Unit Cells

#### Question

Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?

#### Solution

For a face-centred unit cell:

a = 2sqrt2r

It is given that the atomic radius, r = 0.144 nm

So, a = 2sqrt2xx0.144 nm

= 0.407 nm

Hence, length of a side of the cell = 0.407 nm

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#### APPEARS IN

Solution Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell? Concept: Crystal Lattices and Unit Cells - Primitive and Centred Unit Cells.
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