Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (11/3) Ω
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Solution
The resistance of the given resistors is,
R_{1} = 1 Ω, R_{2} = 2 Ω, R_{3} = 3 Ω2

Equivalent resistance, `R'=11/3Omega`
Consider the following combination of the resistors.
Equivalent resistance of the circuit is given by,
`R'=(2xx1)/(2+1)+3=2/3+3=11/3Omega`
Concept: Kirchhoff’s Rules
Is there an error in this question or solution?
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