Advertisement Remove all ads

Given A = 60° and B = 30°, prove that : tan (A - B) = tan A – tan B 1 + tan A . tan B - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum

Given A = 60° and B = 30°,
prove that : tan (A - B) = `(tan"A" – tan"B")/(1 + tan"A".tan"B")`

Advertisement Remove all ads

Solution

LHS = tan(A – B) 

= tan (60° – 30°)

= tan30°

= `(1)/(sqrt3)`

RHS = `(tan"A" –  tan"B")/(1 + tan 60°. tan 30°)`

= `(tan60° – tan30°)/(1+tan 60°.tan30°)`

= `(sqrt3 – 1/(sqrt3))/(1 + sqrt3(1/sqrt3))`

= `(2)/(2sqrt3)`

= `(1)/sqrt3`

LHS = RHS

Concept: Trigonometric Ratios of Some Special Angles
  Is there an error in this question or solution?

APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (B) | Q 1.4 | Page 293
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×