#### Question

Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg, just after it is dropped from the window of a stationary train.

#### Solution 1

1 N; vertically downward

Mass of the stone, *m* = 0.1 kg

Acceleration of the stone, *a* = g = 10 m/s^{2}

As per Newton’s second law of motion, the net force acting on the stone,

*F* =* ma = m*g

= 0.1 × 10 = 1 N

#### Solution 2

Mass of stone = 0.1 kg

Net force, F = mg = 0.1 x 10 = 1.0 N. (vertically downwards).

Is there an error in this question or solution?

Solution Give the Magnitude and Direction of the Net Force Acting on a Stone of Mass 0.1 Kg, Just After It is Dropped from the Window of a Stationary Train, Concept: The Law of Inertia.