#### Question

Let S be the sum, P the product and R the sum of reciprocals of *n* terms in a G.P. Prove that P^{2}R^{n}^{ }= S^{n}

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#### Solution

Let the G.P. be *a*, *ar*, *ar*^{2}, *ar*^{3}, … *ar*^{n}^{ – 1}…

According to the given information,

Hence, P^{2} R^{n} = S^{n}

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Solution for question: Let S Be the Sum, P the Product and R the Sum of Reciprocals of N Terms in a Geometric Progression . Prove that P2rn = Sn concept: Geometric Progression (G. P.). For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)