#### Question

If the 4^{th}, 10^{th} and 16^{th} terms of a G.P. are *x, y *and *z*, respectively. Prove that *x*,* y*,* z *are in G.P.

clickto share

#### Solution

Let *a* be the first term and *r* be the common ratio of the G.P.

According to the given condition,

*a*_{4} = *a* *r*^{3} = *x* … (1)

*a*_{10} = *a* *r*^{9} =* y* … (2)

*a*_{16}^{ }=* a r*^{15 }= *z* … (3)

Dividing (2) by (1), we obtain

Is there an error in this question or solution?

Solution for question: If the 4th, 10th and 16th Terms of a G.P. Are X, Y and Z, Respectively. Prove that X, Y, Z Are in Geometric Progression concept: Geometric Progression (G. P.). For the courses CBSE (Commerce), CBSE (Arts), CBSE (Science)