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The Eθ(M2+/M) value for copper is positive (+0.34V). What is possibly the reason for this? (Hint: consider its high ΔaHθ and low ΔhydHθ) - CBSE (Science) Class 12 - Chemistry

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Question

The Eθ(M2+/M) value for copper is positive (+0.34V). What is possibly the reason for this? (Hint: consider its high ΔaHθ and low ΔhydHθ)

Solution

The Eθ(M2+/M) value of a metal depends on the energy changes involved in the following:

1. Sublimation: The energy required for converting one mole of an atom from the solid state to the gaseous state.

`M_(s) -> M_(g)         triangle_sH("Sublimation energy")`

2. Ionization: The energy required to take out electrons from one mole of atoms in the gaseous state.

`M_(g) -> M_(" "(aq))^(2+)        triangle_iH("Ionization energy")`

3. Hydration: The energy released when one mole of ions are hydrated.

`M_(" "(g))^(2+) -> M_(" "(aq))^(2+)    triangle_"hyd"H("Hydration  energy")`

Now, copper has a high energy of atomization and low hydration energy. Hence, the Eθ(M2+/M) value for copper is positive.

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 NCERT Solution for Chemistry Textbook for Class 12 (2018 to Current)
Chapter 8: The d-block and f-block Elements
Q: 4 | Page no. 217

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Solution The Eθ(M2+/M) value for copper is positive (+0.34V). What is possibly the reason for this? (Hint: consider its high ΔaHθ and low ΔhydHθ) Concept: General Properties of the Transition Elements (D-block).
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