#### Question

Solve the differential equation: `x+ydy/dx=sec(x^2+y^2)` Also find the particular solution if x = y = 0.

#### Solution

`x+ydy/dx=sec(x^2+y^2)...........(i)`

`put x^2+y^2=t`

Differentiating w.r.t. x, we get

`2x+2ydy/dx=dt/dx`

`x+ydy/dx=1/2dt/dx`

`1/2 dt/dx=sect`

`dt/sect=2dx`

Integrating on both sides, we get

`intcostdt=2intdx`

sin t = 2x + c

sin (x^{2} + y^{2}) = 2x + c [1]

When x = y = 0

sin (0 + 0) = 2 (0) + c

c = 0

Particular solution is sin (x^{2} + y^{2}) = 2x

Is there an error in this question or solution?

#### APPEARS IN

Solution Solve the differential equation: x+ydy/dx=sec(x^2+y^2) Also find the particular solution if x = y = 0. Concept: General and Particular Solutions of a Differential Equation.