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Solution - Galvanic Cells - Introduction

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Question

Calculate e.m.f of the following cell at 298 K:

2Cr(s) + 3Fe2+ (0.1M) → 2Cr3+ (0.01M) + 3 Fe(s)

Given: E°(Cr3+ | Cr) = – 0.74 VE° (Fe2+ | Fe) = – 0.44 V

Solution

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Calculate e.m.f. and ∆G for the following cell:

Mg (s) |Mg2+ (0.001M) || Cu2+ (0.0001M) | Cu (s)

`"Given :" E_((Mg^(2+)"/"Mg))^0=−2.37 V, E_((Cu^(2+)"/"Cu))^0=+0.34 V.`

 

 
 
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Mg(s) + Sn2+(0.04M) → Mg2+(0.06M) + Sn(s)

Ecell = 2.23V

Is the reaction spontaneous?

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Given the standard electrode potentials,

K+/K = −2.93V, Ag+/Ag = 0.80V,

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Fe|Fe2+(0.001 M)| |H+(0.01 M)|H2(g) (1 bar)|Pt (s)

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Reference Material

Solution for concept: Galvanic Cells - Introduction. For the courses 12th CBSE (Arts), 12th CBSE (Commerce), 12th CBSE (Science), 12th HSC Science (Computer Science), 12th HSC Science (Electronics), 12th HSC Science (General) , PUC Karnataka Science
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