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Solution - Given that HCF (306, 657) = 9, find LCM (306, 657). - CBSE Class 10 - Mathematics

ConceptFundamental Theorem of Arithmetic

Question

Given that HCF (306, 657) = 9, find LCM (306, 657).

Solution

By the property that LCM X HCF = Product of the two numbers

LCM X 9 = 306 x 657

LCM = `(306 xx 657)/9` = 22338

Therefore LCM(306, 657) = 22338

Is there an error in this question or solution?

APPEARS IN

 NCERT Mathematics Textbook for Class 10 (with solutions)
Chapter 1: Real Numbers
Q: 4 | Page no. 11

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Reference Material

Solution for question: Given that HCF (306, 657) = 9, find LCM (306, 657). concept: null - Fundamental Theorem of Arithmetic. For the course CBSE
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