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# Solution for The slant height of a frustum of a cone is 4 cm and the perimeters (circumference) of its circular ends are 18 cm and 6 cm. find the curved surface area of the frustum. - CBSE Class 10 - Mathematics

#### Question

The slant height of a frustum of a cone is 4 cm and the perimeters (circumference) of its circular ends are 18 cm and 6 cm. find the curved surface area of the frustum.

#### Solution 1

Perimeter of upper circular end of frustum = 18 cm

r1 =18

r1 = 9/π

Perimeter of lower end of frustum = 6 cm

r2 = 6

r2 = 3/π

Slant height (l) of frustum = 4 cm

CSA of frustum = π (r1 + r2l

=pi(9/pi+3/pi)4

= 12x4

= 48 cm2

Therefore, the curved surface area of the frustum is 48 cm2.

#### Solution 2

We have,

Perimeter of upper end, C=18cm,

Perimeter of lower end, c=6 cm and

Slant Height, l=4 cm

Let the radius of upper end be R and the radius of lower end be r.

As, C = 18 cm

⇒2πR = 18

=> R = 18/(2pi)

=> R = 9/picm

Similary c = 6 cm

=> r = 6/(2pi)

=> r = 3/pi cm

Curved surface area of the frustum=π(R + r)l

=pi(9/pi + 3/pi) xx 4

= pi xx 12/pi xx 4

= 48 cm^2

Hence, the curved surface area of the frustum is 48 cm2

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#### APPEARS IN

NCERT Mathematics Textbook for Class 10 (with solutions)
Chapter 13: Surface Areas and Volumes
Q: 2 | Page no. 257
R.D. Sharma 10 Mathematics (with solutions)
Chapter 16: Surface Areas and Volumes
Q: 3

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Solution for question: The slant height of a frustum of a cone is 4 cm and the perimeters (circumference) of its circular ends are 18 cm and 6 cm. find the curved surface area of the frustum. concept: Frustum of a Cone. For the course CBSE
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