Answer 1

(i) A ∪ B = {a, b, c, d} ∪ {c, d, e, g}

= {a, b, c, d, e, g}

∴ (A ∪ B) - C = {a, b, c, d, e, g} - {b, c, e, f}

= {a, d, g}

(ii)  (A ∩ C) = {a, b, c, d} ∩ {b, c, e, f}

= {b, c}

∴ B - (A ∩ C) = {c, d, e, g} - {b, c}

= {d, e, g}

(iii)  B ∩ C = {c, e, d, g} ∩ {b, c, e, f}

= {c, e}

∴ A - (B ∩ C) = (A - B) ∪ (A - C) 

⇒ (B ∩ C) = {c, e}

So, A − (B ∩ C) = {a, b, d}     .....(1)

Now, A − B = {a, b} 

And A − C = {a, d} 

 

The union of two sets has the elements of both sets. 

So, (A − B) ∪ (A − C) = {a, b, d} .....(2)

 

From (1) and (2), we have

A − (B ∩ C) = (A − B) ∪ (A − C)

 

The relation holds True.