Advertisement Remove all ads

From a Solid Cylinder Whose Height is 15 Cm and Diameter 16 Cm, a Conical Cavity of the Same Height and Same Diameter is Hollowed Out. Find the Total Surface Area of the Remaining Solid. - Mathematics


From a solid cylinder whose height is 15 cm and diameter 16 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid. (Use π = 3.14)

Advertisement Remove all ads


We have,

Height of the cylinder = Height of the cone = h = 15 cm and 

Radius of thecylinder = Radius of the cone `= r = 16/2 = 8  "cm" `

Also, the slant height of the cone, `l =sqrt("h"^2 + "r"^2)`

`=sqrt(15^2 + 8^2)`



= 17 cm,


Then total surface area of the remaining solid = CSA of the cone + CSA of the cone + Area of the base

=πrl+ 2πrh + πr

= πr (l + 2h + r)

= 3.14 × 8× (17 + 2 × 15 + 8)

= 3.1× 8 × 55

= 1381.6 cm2

So, the total surface area of the remaining solid is 1381.6 cm2.

Disclaimer: The answer given in the textbook is incorrect. The same has been corrected above.

  Is there an error in this question or solution?
Advertisement Remove all ads


RS Aggarwal Secondary School Class 10 Maths
Chapter 19 Volume and Surface Area of Solids
Formative Assessment | Q 17 | Page 938
Advertisement Remove all ads
Advertisement Remove all ads

View all notifications

      Forgot password?
View in app×