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From a Solid Cylinder of Height 14 Cm and Base Diameter 7 Cm, Two Equal Conical Holes Each of Radius 2.1 Cm and Height 4 Cm Are Cut Off. Find the Volume of the Remaining Solid. - Mathematics

Sum

From a solid cylinder of height 14 cm and base diameter 7 cm, two equal conical holes each of radius 2.1 cm and height 4 cm are cut off. Find the volume of the remaining solid. 

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Solution

we have,

the height of the cylinder, H=14 cm,

the base radius of cylinder, R = `7/2 cm `

the base radius of each conical holes, r =2.1 cm and 

the height of each conical holes, h=4 cm

volume of the remaining solid = volume of thecylinder- volume of 2 conical holes

`=piR^2H - 2xx1/3pir^2h`

`=22/7xx7/2xx7/2xx14-2/3xx22/7xx2.1xx2.1xx4`

= 539 - 36.96

=502.04 cm3

So, the volume of the remaining solid is 502.04 cm3.

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APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 19 Volume and Surface Area of Solids
Exercise 19A | Q 24 | Page 876
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