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MCQ
From a point Q, 13 cm away from the centre of a circle, the length of tangent PQ to the circle is 12 cm. The radius of the circle (in cm) is
Options
A. 25
B. `sqrt313`
C. 5
D. 1
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Solution
The given information can be represented diagrammatically as follows:
Let O be the centre of the circle.
Given: PQ = 12 cm and OQ = 13 cm.
To find: Radius of the circle
PQ is a tangent drawn from the external point Q to the circle.
∠ OPQ = 90° (Radius is perpendicular to the tangent at the point of contact)
On applying Pythagoras theorem in ΔOPQ, we obtain:
OQ2 = OP2 + PQ2
∴ OP2 = OQ2 − PQ2
⇒ OP2 = (13 cm)2 − (12 cm)2
⇒ OP2 = 169cm2 − 144 cm2
⇒ OP2 = 25 cm2
⇒ OP = 5 cm
Thus, the radius of circle is 5 cm.
Hence, the correct answer is C
Concept: Tangent to a Circle
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