Sum
From 25 identical cards, numbered 1, 2, 3, 4, 5, ……, 24, 25: one card is drawn at random. Find the probability that the number on the card drawn is a multiple of:
3
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Solution
There are 25 cared from which one card is drawn.
Total number of elementary event=n(s)=25
From numbers 1 to 25, there are 8 numbers which are multiple of i.e [3,6,9,12,15,18,21,24] Favorable number of event =n(E)=8
Probability of selecting a card with a multiple of 3=
`(n(E))/(n(s))=8/25`
Concept: Type of Event - Complementry
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