shaalaa.com
S

Solution - Calculate Width of the Slit and Width of the Central Maximum. - Fraunhofer Diffraction Due to a Single Slit

Account
User


Login
Register


      Forgot password?
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Question

In a single slit diffraction pattern, the distance between first minima on the right and first minima on the left of central maximum is 4 mm. The screen on which the pattern is displaced, is 2m from the slit and wavelength of light used is 6000Å. Calculate width of the slit and width of the central maximum.

Solution

You need to to view the solution
Is there an error in this question or solution?

Question appears in these question papers

Similar questions

Describe briefly how a diffraction pattern is obtained on a screen due to a single narrow slit illuminated by a monochromatic source of light. Hence obtain the conditions for the angular width of secondary maxima and secondary minima.

view solution

What is 'diffraction of light' ? Explain its two types.

view solution

For a single slit of width "a", the first minimum of the interference pattern of a monochromatic light of wavelength λ occurs at an angle of λa. At the same angle of λa, we get a maximum for two narrow slits separated by a distance "a". Explain.

view solution

Explain why the maxima at `theta=(n+1/2)lambda/a` become weaker and weaker with increasing n

view solution

In the diffraction pattern due to a single slit of width 'd' with incident light of wavelength 'λ', at an angle of  diffraction θ. the condition for first minimum is ....

(a)`lambda sin theta =d`

(b) `d costheta =lambda`

(c)`d sintheta=lambda`

(d) `lambda cos theta=d`

view solution
S