MCQ

Four alternative answers for the following question is given. Choose the correct alternative.

Chords AB and CD of a circle intersect inside the circle at point E. If AE = 5.6, EB = 10, CE = 8, find ED.

#### Options

7

8

11.2

9

Advertisement Remove all ads

#### Solution

If two chords of a circle intersect each other in the interior of the circle, then the product of the lengths of the two tangents of one chord is equal to the product of the lengths of the two segments of the other chord.

∴ AE × EB = CE × ED

⇒ 5.6 × 10 = 8 × ED

⇒ ED = \[\frac{56}{8}\] = 7 units

Hence, the correct answer is 7.

Concept: Touching Circles

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads

Advertisement Remove all ads