Question

Form the differential equation from the relation x² + 4y² = 4b²

Answer 1

Given relation is

x² + 4y² = 4b²

Differentiating w.r.t. x, we get

`2x + 4.2y ("d"y)/("d"x) = 0`

∴ `x + 4y ("d"y)/("d"x)  = 0`, which is the required differential equation.