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Form the pair of linear equations in the following problems, and find their solutions (if they exist) by the elimination method
The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.
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Solution
Let the unit digit and tens digits of the number be x and y respectively. Then, number = 10y + x Number after reversing the digits = 10x + y
According to the given information,
x + y = 9... (1)
9(10y + x) = 2(10x + y)
88y - 11x = 0
- x + 8y =0.....(2)
Adding equation (1) and (2), we obtain
9y = 9
y = 1 (3)
Substituting the value in equation (1), we obtain
x = 8
Hence, the number is 10y + x = 10 × 1 + 8 = 18
Is there an error in this question or solution?