# For which values of a and b does the following pair of linear equations have an infinite number of solutions? 2x + 3y = 7, (a – b) x + (a + b) y = 3a + b – 2 - Mathematics

For which values of a and b does the following pair of linear equations have an infinite number of solutions?

2x + 3y = 7

(a – b) x + (a + b) y = 3a + b – 2

#### Solution

2x + 3y -7 = 0

(a – b)x + (a + b)y - (3a +b –2) = 0

a_1/a_2 = 2/(a-b) = 1/2

b_1/b_2 = 3/(a+b)

c_1/c_2 = -7/-(3a+b-2) = 7/(3a+b-2)

For infinitely many solutions,

a_1/a_2 = b_1/b_2 = c_1/c_2

2/(a-b) = 7/(3a+b-2)

6a + 2b - 4 = 7a - 7b

a - 9b = -4 ... (i)

2/(a-b) = 3/(a+b)

2a + 2b = 3a - 3b

a - 5b = 0 ... (ii)

Subtracting equation (i) from (ii), we get

4b = 4

b = 1

Putting this value in equation (ii), we get

a - 5 × 1 = 0

a = 5

Hence, a = 5 and b = 1 are the values for which the given equations give infinitely many solutions.

Concept: Algebraic Methods of Solving a Pair of Linear Equations - Cross - Multiplication Method
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#### APPEARS IN

NCERT Class 10 Maths
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.5 | Q 2.1 | Page 62