For which values of a and b does the following pair of linear equations have an infinite number of solutions?
2x + 3y = 7
(a – b) x + (a + b) y = 3a + b – 2
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Solution
2x + 3y -7 = 0
(a – b)x + (a + b)y - (3a +b –2) = 0
`a_1/a_2 = 2/(a-b) = 1/2`
`b_1/b_2 = 3/(a+b)`
`c_1/c_2 = -7/-(3a+b-2) = 7/(3a+b-2)`
For infinitely many solutions,
`a_1/a_2 = b_1/b_2 = c_1/c_2`
`2/(a-b) = 7/(3a+b-2)`
6a + 2b - 4 = 7a - 7b
a - 9b = -4 ... (i)
`2/(a-b) = 3/(a+b)`
2a + 2b = 3a - 3b
a - 5b = 0 ... (ii)
Subtracting equation (i) from (ii), we get
4b = 4
b = 1
Putting this value in equation (ii), we get
a - 5 × 1 = 0
a = 5
Hence, a = 5 and b = 1 are the values for which the given equations give infinitely many solutions.
Is there an error in this question or solution?
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