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For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P?
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Solution
If k + 9, 2k – 1 and 2k + 7 are the consecutive terms of A.P., then the common difference will be the same.
∴(2k – 1) – (k + 9) = (2k + 7) – (2k – 1)
∴k – 10 = 8
∴k = 18
Concept: Arithmetic Progression
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