Sum
For the G.P., if r = `1/3`, a = 9, find t7.
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Solution
Given, r = `1/3`, a = 9
tn= arn–1
∴ t7 = `9 xx (1/3)^(7 - 1)`
= `9/3^6`
= `1/81`.
Concept: Sequence and Series - Geometric Progression (G.P.)
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