Sum
For the G.P., if a = `7/243, "r" = 1/3`, find t3.
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Solution
Given, a = `7/243, "r" = 1/3`
tn = arn–1
∴ t3 = `7/243 xx (1/3)^(3 - 1)`
= `7/243 xx (1/3)^2`
= `7/243 xx 1/9`
= `7/2187`.
Concept: Sequence and Series - Geometric Progression (G.P.)
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