For of the non-perfect cubes in Q. No. 20 find the smallest number by which it must be divided so that the quotient is a perfect cube.
The only non-perfect cube in question number 20 is 243.
On factorising 243 into prime factors, we get: \[243 = 3 \times 3 \times 3 \times 3 \times 3\] On grouping the factors in triples of equal factors, we get:
Thus, 243 should be divided by 9 to make it a perfect cube.
Video Tutorials For All Subjects
- Concept of Cube Root