For an A.P. t_{3 =} 8 and t_{4} =12, find the common difference d.

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#### Solution

Given:

t_{3}=8 and t_{4}=12

Since, t_{n}=a+(n - 1)d

t_{3}=a+(3-1)d

8=a+2d… (i)

t_{4}=a+(4-1)d

12=a+3d … (ii)

Subtracting (i) from (ii), we get

d=4

The common difference is 4.

Concept: Arithmetic Progression

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