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For an A.P., t4 = 12 and its common difference d = – 10, then find tn - Algebra

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Sum

For an A.P., t4 = 12 and its common difference d = – 10, then find tn 

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Solution

t4 = 12, d = – 10    .....[Given]

Since tn = a + (n – 1)d,

t4 = a + (4 – 1)(– 10)

∴ 12 = a + 3(– 10)

∴ 12 = a – 30

∴ a = 42

tn = a + (n – 1)d

= 42 + (n – 1)(– 10)

= 42 – 10n + 10

= 52 – 10n

Concept: Arithmetic Progression
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