Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum
For all sets A and B, A – (A ∩ B) = A – B
Advertisement Remove all ads
Solution
Given: There are two sets A and B
To prove: A – (A ∩ B) = A – B
Take L.H.S
A – (A ∩ B)
= A ∩ (A ∩ B) .....[∵ A – B = A ∩ B’]
= A ∩ (A ∩ B’)’
= A ∩ (A’ ∪ B’) ......[∵ (A ∩ B)’ = A’ ∪ B’]
= (A ∩ A’) ∪ (A ∩ B’)
∵ Distributive property of set:
(A ∩ B) ∪ (A ∩ C) = A ∩ (B ∪ C)}
= Φ ∪ (A ∩ B’) ......[∵ A ∩ A’ = Φ]
= A ∩ B’
= A – B ......[∵ A – B = A ∩ B’]
= R.H.S
Hence Proved
Concept: Operations on Sets - Union of Sets
Is there an error in this question or solution?