Advertisement Remove all ads

Advertisement Remove all ads

Advertisement Remove all ads

Sum

Following tale gives income (X) and expenditure (Y) of 25 families:

Y/X |
200 – 300 |
300 – 400 |
400 – 500 |

200 – 300 |
IIII I | IIII I | I |

300 – 400 |
– | IIII | IIII I |

400 – 500 |
– | – | II |

Find How many families have their income Rs. 300 and more and expenses Rs. 400 and less?

Advertisement Remove all ads

#### Solution

Bivariate frequency distribution table for Income (X) and Expenditure (Y) is as follows:

Y/X |
200 – 300 |
300 – 400 |
400 – 500 |
Total (f_{y}) |

200 – 300 |
6 | 6 | 1 | 13 |

300 – 400 |
0 | 4 | 6 | 10 |

400 – 500 |
0 | 0 | 2 | 2 |

Total (f_{x}) |
6 | 10 | 9 | 25 |

The cells 300 – 400 and 400 – 500 are having income ₹ 300 and more and the cells 200 – 300 and 300 – 400 are having expenditure ₹ 400 and less. Now, the following table indicates the number of families satisfying the above condition.

Y/X |
300 – 400 |
400 – 500 |
Total |

200 – 300 |
6 | 1 | 13 |

300 – 400 |
4 | 6 | 10 |

Total |
10 | 7 | 17 |

∴ There are 17 families with income ₹ 300 and more and expenditure ₹ 400 and less.

Concept: Statistics (Entrance Exam) - Bivariate Frequency Distribution

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads