Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum
Floor of a room is of dimensions 5 m × 4 m and it is covered with circular tiles of diameters 50 cm each as shown in figure. Find the area of floor that remains uncovered with tiles. (Use π = 3.14)
Advertisement Remove all ads
Solution
Length of the floor = l = 5 m
Breadth of the floor = b = 4 m
∴ Area of the floor = l × b = 5 × 4 = 20 m2
Now, Diameter of each circular tile = 50 cm
∴ Radius of each circular tile = r = 25 cm = 0.25 m
Area of one circular tile = πr2
= 3.14 × (0.25)2
= 0.19625 m2
Area of such 80 tiles = 80 × 0.19625
= 15.7 m2
Area of the floor that remains uncovered with tiles =
Area of the floor – Area of all 80 circular tiles
= 20 – 15.7
= 4.3 m2
Hence, the required area of floor that remains uncovered with tiles is 4.3 m2.
Concept: Areas of Sector and Segment of a Circle
Is there an error in this question or solution?