# Five Bad Oranges Are Accidently Mixed with 20 Good Ones. If Four Oranges Are Drawn One by One Successively with Replacement, Then Find the Probability Distribution of Number of Bad Oranges Drawn. - Mathematics

#### Question

Five bad oranges are accidently mixed with 20 good ones. If four oranges are drawn one by one successively with replacement, then find the probability distribution of number of bad oranges drawn. Hence find the mean and variance of the distribution.

#### Solution

Let be the random variable denoting the number of bad oranges drawn.
P (getting a good orange) = $\frac{20}{25} = \frac{4}{5}$

P (getting a bad orange) = $\frac{5}{25} = \frac{1}{5}$

The probability distribution of X is given by

 X 0 1 2 3 4 P(X) $\left( \frac{4}{5} \right)^4$ =$\frac{256}{625}$ $^{4}{}{C}_1 \left( \frac{4}{5} \right)^3 \left( \frac{1}{5} \right)$ =$\frac{256}{625}$ $^{4}{}{C}_2 \left( \frac{4}{5} \right)^2 \left( \frac{1}{5} \right)^2$ =$\frac{96}{625}$ $^{4}{}{C}_3 \left( \frac{4}{5} \right) \left( \frac{1}{5} \right)^3$ =$\frac{16}{625}$ $\left( \frac{1}{5} \right)^4$ =$\frac{1}{625}$

Mean of X is given by

$\overline{X} = \sum P_i X_i$

$= 0 \times \frac{256}{625} + 1 \times \frac{256}{625} + 2 \times \frac{96}{625} + 3 \times \frac{16}{625} + 4 \times \frac{1}{625}$

$= \frac{1}{625}\left( 256 + 192 + 48 + 4 \right)$

$= \frac{4}{5}$

Variance of X is given by $\text{ Var } (X) = \sum P_i {X_i}^2 - \left( \sum P_i X_i \right)^2$

$= 0 \times \frac{256}{625} + 1 \times \frac{256}{625} + 4 \times \frac{96}{625} + 9 \times \frac{16}{625} + 16 \times \frac{1}{625} - \left( \frac{4}{5} \right)^2$

$= \frac{1}{625}\left( 256 + 384 + 144 + 16 \right) - \frac{16}{25}$

$= \frac{800}{625} - \frac{16}{25}$

$= \frac{400}{625}$

$= \frac{16}{25}$

Thus, the mean and vairance of the distribution are $\frac{4}{5}$ and  $\frac{16}{25}$ , respectively.

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Mathematics for Class 12 (Set of 2 Volume) (2018 (Latest))
Chapter 33: Binomial Distribution
33.2 | Q: 27 | Page no. 26

#### Video TutorialsVIEW ALL 

Five Bad Oranges Are Accidently Mixed with 20 Good Ones. If Four Oranges Are Drawn One by One Successively with Replacement, Then Find the Probability Distribution of Number of Bad Oranges Drawn. Concept: Random Variables and Its Probability Distributions.