Tamil Nadu Board of Secondary EducationHSC Commerce Class 11

Find y2 for the following function: y = log x + ax - Business Mathematics and Statistics

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Sum

Find y2 for the following function:

y = log x + ax

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Solution

y = log x + a

`y_1 = "dy"/"dx" = 1/x + "a"^x log "a"`   ....`[because "d"/"dx" ("a"^x) = "a"^x log "a"]`

`y_2 = ("d"^2y)/"dx"^2 = "d"/"dx"(1/x) + log "a" "d"/"dx" ("a"^x)`

`= (-1)/x^2 + (log "a")("a"^x log "a")`

`= (-1)/x^2 + ("a"^x log "a")^2`

Concept: Differentiation Techniques
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Chapter 5: Differential Calculus - Exercise 5.9 [Page 123]

APPEARS IN

Tamil Nadu Board Samacheer Kalvi Class 11th Business Mathematics and Statistics Answers Guide
Chapter 5 Differential Calculus
Exercise 5.9 | Q 1. (ii) | Page 123
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