Answer 1

`x^2 + 6y^2 =5xy`

Dividing both sides by `y^2` we get

`x^2/y^2 + (6y^2)/y^2 = (5xy)/(y^2)`

`(x/y)^2 + 6 = 5(x/y)`

`(x/y)^2 - 5(x/y) + 6 = 0`

Let `x/y = a`

`a^2 - 5a + 6 = 0`

=> (a - 2)(a - 3) = 0

=> a = 2, 3

hence `"x"/"y"` = 2, 3