Answer 1

`[(x, 0),(-3, 1)][(1,1),(0, y)] = [(2,2),(-3, -2)]`

`[(x+ 0, x + 0),(-3+0, -3 + y)] = [(2, 2),(-3, -2)]`

`[(x, x),(-3, -3 + y)] = [(2,2),(-3, -2)]`

Comparing the corresponding elements we get

x = 2

`-3 + y = -2 => y = 1`