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Find X, If ( − 1 2 ) − 19 × ( − 1 2 ) 8 = ( − 1 2 ) − 2 X + - Mathematics

Sum

Find x, if
\[\left( \frac{- 1}{2} \right)^{- 19} \times \left( \frac{- 1}{2} \right)^8 = \left( \frac{- 1}{2} \right)^{- 2x + 1}\]

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Solution

We have:

\[\left( \frac{- 1}{2} \right)^{- 19} \times \left( \frac{- 1}{2} \right)^8 = \left( \frac{- 1}{2} \right)^{- 2x + 1}\]

`((-1)/2)^(-11)=((-1)/2)^(-2x+1)`

\[( a^m \times a^n = a^{m + n} )\]

-11 = -2x + 1

-12 = -2x

6 = x

x = 6

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APPEARS IN

RD Sharma Class 8 Maths
Chapter 2 Powers
Exercise 2.2 | Q 12.2 | Page 19
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