Answer 1

We have: 

\[\frac{27}{64} = \frac{3 \times 3 \times 3}{8 \times 8 \times 8} = \frac{3^3}{8^3} = \left( \frac{3}{8} \right)^3\]

Therefore,

\[\frac{27}{64}\]  is a cube of \[\frac{3}{8}\] .