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Find the Wave Number of a Photon Having Energy of 2.072 Ev - Physics

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Find the wave number of a photon having energy of 2.072 eV

Given : Charge on electron = 1.6 x 10-19 C,

           Velocity of light in air = 3 x 108 m/s,

           Planck’s constant = 6.63 x 10-34 J-s.

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Solution

E = hv

`:.v=E/h`

`v=C/lambda`

∴ Wave number

`1/lambda=v/c`

`=E/(hc)`

`=(2.072xx1.6xx10^(-19))/(6.63xx10^(-34)xx3xx10^8`

`=1/lambda=1.667xx10^6m^(-1)`

Concept: Einstein’s Equation - Particle Nature of Light
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